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Solve the equation by completing the square? 12x= -2x² + 8 A. x= -3 + √13, -3, - √13 B. x= 3 + √13, 3 -√13 C. x= 2,4 D. x= -2,-4
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\[2x ^{2}+12x-8=2(x+3)^2-26=0 => (x+3)^2=13 => x=-3+\sqrt{13} , x=-3-\sqrt{13}\]
So B?
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