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7. What is the value of 7P3? with permutations
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\[7\times 6\times 5\]
210
840?
210 is right
\[n P r=\frac{n!}{(n-r)!}\]
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that is the formula
\[7 P 3=\frac{7!}{(7-3)!}=\frac{7!}{4!}=\frac{7 \cdot 6 \cdot 5 \cdot 4!}{4!}=7 \cdot 6 \cdot 5 \]
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