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Find two numbers whose product is 2 and the sum of whose reciprocals is 33/8.
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Let x and y be two numbers. The product is 2 means\[xy=2\]The sum of whose reciprocals is 33/8 means\[\frac 1 x +\frac 1y =\left( 33 \over 8 \right)\] Can you solve for x and y?
Would I start by multiplying the bottom equation by xy?
Sure, that is one way to solve.
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