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Find the equation of the parabola that has a vertex of (4,1) and passes through the point (3,0)
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since you know the vertex, the vertex form would seem a good start
y = a(x-vx)+vy ; where vertex = (vx,vy)
forgot my ^2
lets fill in the specifics now: y = a(x-4)^2+1 now, when x=3, and y=0; what do we get to work with? 0 = a(3-4)^2 +1 0 = a(-1)^2 +1 0 = a +1 -1 = a
so write it up with the proper a value and it should be good. you might have to expand it to match a choice
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