Question

question I'm stuck on!! help!!

Answer 1

Where are you stuck exactly? We solved 2-3 previous questions of yours which were the same thing with different values.

Answer 2

\[\begin{array}{l} \frac{2}{x+2}+\frac{1}{5}=\frac{6}{x+5} \\ \text{Multiply both sides by }x+2: \\ \frac{x+2}{5}+2=\frac{6 (x+2)}{x+5} \\ \text{Multiply both sides by }x+5: \\ (x+5) \left(\frac{x+2}{5}+2\right)=6 (x+2) \\ \text{Expand out terms on both sides:} \\ \frac{x^2}{5}+\frac{17 x}{5}+12=6 x+12 \\ \text{Subtract }(6 x+12)\text{ from both sides:} \\ \frac{x^2}{5}-\frac{13 x}{5}=0 \\ \text{Solve the quadratic equation by completing the \square:}\text{$\backslash $n$\backslash $n}\text{Divide both sides by }\frac{1}{5}: \\ x^2-13 x=0 \\ \text{Add }\frac{169}{4}\text{ \to both sides:} \\ x^2-13 x+\frac{169}{4}=\frac{169}{4} \\ \text{Factor the \left hand side:} \\ \left(x-\frac{13}{2}\right)^2=\frac{169}{4} \\ \text{Take the \square \root of both sides:} \\ \left|x-\frac{13}{2}\right|=\frac{13}{2} \\ \text{Eliminate the absolute value:} \\ x-\frac{13}{2}=-\frac{13}{2}\text{ or }x-\frac{13}{2}=\frac{13}{2} \\ \text{Add }\frac{13}{2}\text{ \to both sides:} \\ x=0\text{ or }x-\frac{13}{2}=\frac{13}{2} \\ \text{Add }\frac{13}{2}\text{ \to both sides:} \\ x=0\text{ or }x=13 \\\end{array}\]

Answer 3

thanks sam

Answer 4

@.Sam. , you just wasted a lot of time Texing (somethnig tells me that the asker only cares about that last line)

Answer 5

true story lol

Answer 6

Fortunately, there exists a report button for answer fiends.