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Mathematics 22 Online
OpenStudy (anonymous):

√2x-5=3

OpenStudy (lgbasallote):

\[\sqrt{2x} - 5 = 3?\]

OpenStudy (anonymous):

haha yes, i dont know how to solve for X

OpenStudy (lgbasallote):

add 5 to both sides

Parth (parthkohli):

1) Add 5 to both sides. 2) Square both sides. 3) Solve for x.

OpenStudy (anonymous):

(2x-5)^1/2=3 on squring both sides 2x-5=9 2x=9+5 2x=4 x=2

Parth (parthkohli):

@shona1826 Check your answer, it's wrong :P

OpenStudy (lgbasallote):

@ParthKohli you're one to say

OpenStudy (anonymous):

sorry guys.... its 7 x=7

OpenStudy (anonymous):

lol is it wrong ?

Parth (parthkohli):

\(\Large \color{MidnightBlue}{\rightarrow \sqrt{2x} = 8 }\) \(\Large \color{MidnightBlue}{\rightarrow 2x = 64 }\) \(\Large \color{MidnightBlue}{\rightarrow x = 32 }\)

Parth (parthkohli):

It's not square root of whole 2x - 7

OpenStudy (lgbasallote):

5 not 7

Parth (parthkohli):

Lol yes

Parth (parthkohli):

But I solved it correctly.

OpenStudy (lgbasallote):

think so?

Parth (parthkohli):

Yes

OpenStudy (lgbasallote):

well if you're so confident...

OpenStudy (anonymous):

im confused now !

OpenStudy (anonymous):

fianally ans is 7

Parth (parthkohli):

It's 32..

OpenStudy (anonymous):

no its 7

OpenStudy (anonymous):

haha ummm !

Parth (parthkohli):

\(\Large \color{MidnightBlue}{\rightarrow \sqrt{2x} - 5 = 3 }\) \(\Large \color{MidnightBlue}{\rightarrow \sqrt{2x} = 8 }\) \(\Large \color{MidnightBlue}{\rightarrow 2x = 8^2 }\) \(\Large \color{MidnightBlue}{\rightarrow 2x = 64 }\) \(\Large \color{MidnightBlue}{\rightarrow x = 32 }\)

OpenStudy (anonymous):

2x-5=9 2x=9+5 2x=14 x=7

Parth (parthkohli):

See the square root..

Parth (parthkohli):

And also, sqrt2x - 5 = 3 not 9

OpenStudy (anonymous):

tell me the squre root of whole or only 2x?

Parth (parthkohli):

Only 2x

OpenStudy (anonymous):

seabee?

Parth (parthkohli):

See on the top, seabee said yes to lgba..

OpenStudy (anonymous):

only 2x

OpenStudy (lgbasallote):

*said yes* what?!!

Parth (parthkohli):

then mine is correct

OpenStudy (lgbasallote):

you're really confident bout that huh @ParthKohli

Parth (parthkohli):

Yes..

OpenStudy (anonymous):

if the squre root is on only 2x then parth is correct

OpenStudy (inkyvoyd):

*gives igbiw a medal*

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