Question

Factorise the following expressions;
a) x²-x)-(2-2x)

b) 4x²(x-2)+2x(x-2)

Answer 1

Go ahead and start factorizing it. then tell us where you're stuck

Answer 2

hint: \[(2 - 2x) = -(2x - 2)\]

Answer 3

(x²-x)-(2-2x)
= x² -x -2 + 2x
= x² +x -2
= x² +2x -x -2
= x(x+2) - (x+2)
= (x-1)(x+2)

Answer 4

OR
\[(x^2 - x) + (2x - 2)\] \[x(x - 1) + 2(x-1)\] \[(x-1)(x+2)\] whichever you like better

Answer 5

4x²(x-2)+2x(x-2)
= (4x²+2x)(x-2)
Since there is 2x in the terms in the first bracket, take it out
= 2x(2x+1)(x-2)

Answer 6

My favourite way to do (a):
(x²-x)-(2-2x)
= x² -x -2 + 2x
= x² +x -2

= (x+2)(x-1)