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Factorize the following expression please. x to the power of 4-16
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\[x^4 - 16\] that's difference of two squares
Hint: \[(a^2 - b^2) = (a+b)(a-b)\]
x^4-16=(x^2+4)(x^2-4)=(x^2+4)(x+2)(x-2)
\(\Large \color{MidnightBlue}{\Rightarrow x^4 - 4^2 }\) \(\Large \color{MidnightBlue}{\Rightarrow (x^2)^2 - 4^2 }\) Try to factorize this by this identity: a^2 - b^2 = (a + b)(a - b)
lol @ParthKohli
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What? @lgbasallote
Thank you. I just was not sure about (x²+4). Have a nice day.
Yw :D :P
welcome
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