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(square root of 7 - square root of 11)^2
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18 - 2 square root of 77
\[(\sqrt 7 -\sqrt {11})^2\] Use the formula \[(a-b)^2=a^2-2ab+b^2\] \[(\sqrt 7 -\sqrt {11})^2=(\sqrt 7)^2- 2\times \sqrt 7 \sqrt{11} +(\sqrt {11})^2\] \[(\sqrt 7 -\sqrt {11})^2=7-2 \times \sqrt {77}+11\] Can you simplify now?
16*\[\sqrt{11}\]
@ngtts \[ 7 -( 2\times \sqrt {11} )+11\] Now simplify it:)
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