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The picture shows a cable car that carries tourists to the top of a mountain AC. What is the distance, in feet, that the cable car has to travel to carry tourists from point B to point A? 5000 cot 37˚ 5000/ sec37 5000 cosec 37˚ 5000/cos ec37
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If you remember SOH CAH TOA, you should use SOH. so,\[ \sin(37)=\frac{opposite}{hypotenuse}\] \[ \sin(37)=\frac{5000}{hypotenuse}\]
rearranging you should get \[hypotenuse =\frac{5000}{\sin(37)}\]
and if you still remember \[sinx=\frac{1}{cosec x}\] So, its hypotenuse =5000cosec(37)
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