Question

What is the lateral area of a triangular prism with base edges all equaling 3 meters and a height of 5 meters?

Answer 1

at first the base area
s1=(1/2)*a*b*sinr=1/2*3^2*sin60=\[(9\sqrt{3})/4\]
and the side area s2=5*3*3=45
s=s1+s2=45+\[(9\sqrt{3})/4\]