Question

the region in the first quadrant bound by the graph of y=secx, x=pi/4 and the axes is rotated about the x-axis. what is the volume of the solid generated?

Answer 1

i that the region im flipping over the x-axis?

Answer 2

that's what it says
I would recommend disk method

Answer 3

is that one squared?

Answer 4

yes, the area of each disk is given by the formula\[A=\pi r^2\] and we need to find r in this case....

Answer 5

wouldnt it be pi/4?

Answer 6

not the area of any circle is\[A=\pi r^2\]the limits of your integral will be 0 and \(\large \frac\pi4\)