There are 2 blue cards, 3 green cards, 1 yellow card, and 4 pink cards. What is the probability of drawing a green card, NOT replacing it, and then drawing another green card?
A. 9/100
B. 3/50
C. 1/15

Question

There are 2 blue cards, 3 green cards, 1 yellow card, and 4 pink cards. What is the probability of drawing a green card, NOT replacing it, and then drawing another green card? 
A. 9/100
B. 3/50
C. 1/15

jim_thompson5910 · Answer

P(green and green) = P(green)*P(green)


P(green and green) = (3/10)*(2/9)


P(green and green) = 6/90


P(green and green) = 1/15


So the answer is choice C