Question

What are the solutions of x^2 + 8x - 20 = 0?
Answer
x = 2, x = 10
x = -2, x = -10
x = 2, x = -10
x = -2, x = 10

Answer 1

x=2 , x = -10

Answer 2

factorise the quadratic...

find the factors of -20 that add to 8... one is positive, one is negative.

then its

(x - factor1)(x + factor2) = 0

Answer 3

Use the quadratic formula:
x = -b \[x = -b \pm \sqrt{b^2 - 4ac} /2\]

Answer 4

Or factor⇪

Answer 5

(x+10)(x-2)=0