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a closed cylindrical can of tennis balls has a diameter of 4 inches. if the can contains 3 balls stacked so that they touch the top and bottom inside covers of the can, what is the volume of the space in the can not filled with balls? (round to the nearest hunderedth of a cubic inch)
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I think the question is assuming that the diameter of each ball is also 4 inches. So \[v=pi*r^2*h\]
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