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\[4a ^{3}b ^{2}\times3a ^{-4}b ^{-3}\] Simplify.
\[12a ^{-1}b ^{-1}\] Is it that?
Use the same rule as before. a^b * a^c = a^(b+c) Then, use: \[a^{-b} = \frac{1}{a^b}\]
Right so far.
So \[12/ab\]
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?
Yes. \[\frac{12}{ab}\]
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