Question

(x-3)^2/(9)-(y-2)^2/(16)=1
find the center of the hyperbola

Answer 1

\[(x-3)^2/(9)-(y-2)^2/(16)=1\]

Answer 2

Which is ( h, k)!

Answer 3

Set each brackets =0
(x-3)=0
x=3
(y-2)=0
y=2