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Factor the equation 4x^2-20x=0
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please show work
\[4x^2-20x=0\]\[(4)(x)(x)-(4)(5)(x)=0\]\[=4x(x-5)=0\] \[x=0,5\]
yup answer is x=0 x=5 4x(x-5)=0 x=0,x=5
@rickybobby13 gets??
I still I'm having a hard time understanding this.
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which step do you not fully understand
how to go from \[(4)(x)(x)-(4)(5)(x)=0\] to \[4x(x-5)=0\]
he isolate the 4x because it is common
|dw:1337313474865:dw|
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