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Find the center of the circle with equation x^2+y^2-4x+6y+1=0
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For equation of circle in this form: x^2 + y^2 +Dx +Ey +F =0 centre = (-D/2 , -E/2) Now, D= -4, E = 6, can you find the answer?
-2,-3?
Nope, y-coordinate is correct, not for the x.
for x coordinate, it's equal to -(-4)/2 =4/2 =?
Ok! Makes sense now. Thx!
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