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OpenStudy (anonymous):
In an examination it is required to get 40% of the aggregate marks to pass. A student gets 261 marks and is declared failed by 4% marks. What are the maximum aggregate makrs a student can get?
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OpenStudy (kropot72):
261 marks is (40 - 4) = 36% of the aggregate marks. Maximum aggregate marks = 261/0.36 Now can you solve it?
OpenStudy (anonymous):
36 % = 261 => 100 % = 261 * 100/36= ?
OpenStudy (kropot72):
jaikiran323 can you use a calculator?
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