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\[\sqrt{(2x)^13}\]
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Hahaha, that's suppose to be 13 :D
=\[((2x)^{\frac{1}{2}})^{13}\]\[\large{(2x)^{\frac{13}{2}}}\]
Can you please tell me what did you do?
\[\large{}\sqrt{x}=x^{\frac{1}{2}}\]
and \[\large{}(x^n)^m=x^{n \times m}\]
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an algebra answer....\[\LARGE x^{\frac{a}{b}} = \sqrt[b]{x^a}\]
Ah! Thank you :)
:D
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