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r(x-3)/5P = s(2x+1)/Q Make X the subject? :o
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ill walk u through this first thing do cross multiplication
Ok :o
do u know how to do that?
Yes xD
ok do it xD
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sec
oky:)
r(x-3)Q=S(2x+1)5P?
yeah now expand the brackets
rx-r3(Q) = 2sx+s(5P)
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no its rQx-3rQ=10spx+5sp because ur multiplyin the bracket by rQ not just r
Ah ok, sorry :)
yeah now collect the terms that have x in them on one side and factor out the x
rQx-10spx = 5sp+3rQ
exactly,, now factor out the x from the Left side
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x(rQ-10sp)
yup now divide both sides by the coeffecient of x
x = (5sp+3rQ)/rQ-10sp w0w!
:D yay
Your awesome!!!!
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* high five *
lol *high five"
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