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Mathematics 17 Online
OpenStudy (asylum15):

r(x-3)/5P = s(2x+1)/Q Make X the subject? :o

OpenStudy (lalaly):

ill walk u through this first thing do cross multiplication

OpenStudy (asylum15):

Ok :o

OpenStudy (lalaly):

do u know how to do that?

OpenStudy (asylum15):

Yes xD

OpenStudy (lalaly):

ok do it xD

OpenStudy (asylum15):

sec

OpenStudy (lalaly):

oky:)

OpenStudy (asylum15):

r(x-3)Q=S(2x+1)5P?

OpenStudy (lalaly):

yeah now expand the brackets

OpenStudy (asylum15):

rx-r3(Q) = 2sx+s(5P)

OpenStudy (lalaly):

no its rQx-3rQ=10spx+5sp because ur multiplyin the bracket by rQ not just r

OpenStudy (asylum15):

Ah ok, sorry :)

OpenStudy (lalaly):

yeah now collect the terms that have x in them on one side and factor out the x

OpenStudy (asylum15):

rQx-10spx = 5sp+3rQ

OpenStudy (lalaly):

exactly,, now factor out the x from the Left side

OpenStudy (asylum15):

x(rQ-10sp)

OpenStudy (lalaly):

yup now divide both sides by the coeffecient of x

OpenStudy (asylum15):

x = (5sp+3rQ)/rQ-10sp w0w!

OpenStudy (lalaly):

:D yay

OpenStudy (asylum15):

Your awesome!!!!

OpenStudy (asylum15):

* high five *

OpenStudy (lalaly):

lol *high five"

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