Question

Use long division to find the quotient below.

(x2 + 3x - 18) (x - 3)







A.

x - 6








B.

x + 15








C.

x + 6








D.

x - 15

Answer 1

\[(x^2+3x-18)\div (x-3)\]
Let's divide

_______________________________
(x-3)|x^2+3x-18
x^2 divided by x=x
so the first term of quotient is x

x
_______________________________
(x-3)|x^2+3x-18
x^2-3x

We need to subtract now


x
_______________________________
(x-3)|x^2+3x-18
-(x^2-3x)
_____________________
6x
and -18 will come down



x
_______________________________
(x-3)|x^2+3x-18
-(x^2-3x)
_____________________
6x-18

Do you understand till here?