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The necessary part of the law of sines is: \[\frac{a}{\sin A}=\frac{b}{\sin B}\] When the triangle is drawn, line BC is a = 18, line AC is b = 22, angle theta is A and angle B = 135 degrees \[\frac{18}{\sin \theta}=\frac{22}{\sin 135}\] \[\sin \theta=\frac{18}{22}\times \sin 135\] Can you calculate this?
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