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What value of b makes the polynomial below a perfect square? x2 + bx + 16 b = A. 16 B. 8 C. 2 D. 4
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(x + 4)^2 = x2 + bx + 16 Solve for b.
\(\Large \color{MidnightBlue}{\Rightarrow (x + 4)^2 }\) This is the value, clearly, as (x + 4)^2 will be x^2 + 16 + 2*4*x
x^2 + 8x + 16 = x^2 + bx + 16 So b is 8.
\(\Large \color{MidnightBlue}{\Rightarrow (a + b)^2 = a^2 + 2a + b^2 }\)
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