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Factor this trinomial. x2 + 3x - 4
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\[x ^{2}+4x-x+4\]
= (x + 4)(x - 1)
Think of what 2 numbers multiply to (-4) and add to (+3)
That's right.
\[x(x+4)-1(x+4)\] \[(x+4)(x-1)\]
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4 has factors 1,2,2. now 1 - 2*2 can be written as '-3' so split the middle term '-3x' as 'x - 4x' --- then take common and proceed.
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