Question

Find the axis of semetry and the vertex of the graph y=-x^2-10x+17

Answer 1

\( y=-x^2-10x+17\)

\( y=-(x^2+10x)+17\)

\( y=-(x^2+10x +(10/2)^2)+17+(10/2)^2\)

\( y=-(x^2+10x +(5)^2)+17+25\)

\( y=-(x^2+5)^2+42\)

\( y=-(x^2-(-5))^2+42\)

The vertex is \(-5,42\)