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Mathematics 7 Online
OpenStudy (anonymous):

Can you help me Simplify... (2/3a) multiply by (2/a^2) a. (4/3a^2) where a ≠ 0 b. (1/a^2) where a ≠ 0 c. (4/3a^3) where a ≠ 0 d. (4/3a^2) My guess is (a) Thanks

jimthompson5910 (jim_thompson5910):

Multiply the numerators 2 and 2 to get...?

OpenStudy (amorfide):

read the question wrong oops

OpenStudy (amorfide):

|dw:1337369687194:dw|

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