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OpenStudy (anonymous):
f(x) = (2x^2+3x+1)/(2x+1) simplified
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OpenStudy (pfenn1):
\[f(x)=\frac{2x^2+3x+1}{2x+1}\] The first thing I would do is factor the numerator\[2x^2+3x+1=(2x+1)(x+?)\]
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