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Simplify (n^3-n)(n-2)!
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amorfide, it's (n-2)! (factorial)
well this is embarrassing :P
\[\begin{align} (n^3-n)(n-2)!&=n(n^2-1)(n-2)!\\ &=n(n+1)(n-1)(n-2)!\\ &=(n+1)n(n-1)(n-2)!\\ &=(n+1)! \end{align}\]
thanks so much asnaseer!
yw
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