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solve for x (6x)^07^97^x=7^5
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\[(6x)^{0}7^{9}7^{x}=7^{5}\]
I would say x is 5 but let me check
k
it is 5
oh wait that is a 9 it looked like zero
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x = -4 in that case
just use fact that any number to the 0 power is 1
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