Question

i need helpppp
-3x+9
9

Answer 1

division?

Answer 2

yes

Answer 3

\(\Large \color{MidnightBlue}{\Rightarrow {-3(x - 3) \over -3(-3)} }\)

\(\Large \color{MidnightBlue}{\Rightarrow {x - 3 \over -3} }\)

\(\Large \color{MidnightBlue}{\Rightarrow {-x + 3 \over 3} }\)

Answer 4

Got it now?

Answer 5

\[\frac{-3x+9}{9}\]\[=\frac{3(-x+3)}{3(3)}\]\[=\frac{-x+3}{3}\]\[=\frac{-x}{3}+\frac33\]\[=1-\frac x3\]

Answer 6

First, I factored both the numerators and denominators, then I cancelled them out.

Answer 7

thats' rite parth i was also doing the same..but u done it first..

Answer 8

Hahaha :D

Answer 9

i kinda get it, thanks (:

Answer 10

Haha no probs :D

Answer 11

keep it up parh..;)

Answer 12

Thanks @nilankshi

Answer 13

yr welcome parth