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what is the square root of 3+4i? explain please.
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\[ \sqrt{3+4 i}=(a+i b)\\ 3+ 4 i = a^2 - b^2 + 2 a b i a^2 - b^2 =3\\ 2 a b = 4 \] Solve for a and b
One of the solution is a=2 and b=1
2 + i is the answer
yes it has two answers
Of course -(2 + i) is a solution
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z^1/n has n different solutions .always!
Unless z =0.
yeap
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