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Physics 8 Online
OpenStudy (anonymous):

A stone is thrown vertically upwards with an initial velocity of 25ms^-1 . Find the height that is reached by this stone after 3s. (Acceleration due to gravity = 10 ms^-2)

sam (.sam.):

a=-g u=25 t=3 h=ut+(1/2)at^2

sam (.sam.):

you still there?

OpenStudy (asylum15):

Acceleration = negative G since you are moving up when gravity acts downwards.

OpenStudy (anonymous):

@.Sam. Thank you !! I know where i did wrong. I didnt put the negative sign! :D

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