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In ∆PQR, find the measure of ∡P 30.4° 35.9° 54.1° 59.6°
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Use \[\tan \theta\] to find the angle as the value of base and altitude is already given
but its asking to find angle p
tanP = RQ/QP
then take inverse.
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so basically, \[P=tan^{-1}(\frac{RQ}{QP})\]
@apoorvk exactly
thanks so its 59.6
Nope.
than what is it
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Do you know what an opposite side is of a specified angle? Do you know what an adjacent side of the angle P ? Do you know what defines tan of angle P? You need to know this to solve this problem.
Also do you know what\[\tan ^{-1}\] means.
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