Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Factor completely: 4x^2 + 16x A) 4(x2 + 4x) B) x(4x + 16) C) 4x(x + 4) D) Prime

Parth (parthkohli):

The common factor is 4x, I guess you got the answer by now.

OpenStudy (anonymous):

Take out common factor(4x)

OpenStudy (anonymous):

4x^2 + 16x = 4x(x + 4)

Parth (parthkohli):

The common factor is outside the bracket. Another hint.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!