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OpenStudy (anonymous):
Factor completely: 4x^2 + 16x A) 4(x2 + 4x) B) x(4x + 16) C) 4x(x + 4) D) Prime
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Parth (parthkohli):
The common factor is 4x, I guess you got the answer by now.
OpenStudy (anonymous):
Take out common factor(4x)
OpenStudy (anonymous):
4x^2 + 16x = 4x(x + 4)
Parth (parthkohli):
The common factor is outside the bracket. Another hint.
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