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A square with each side measuring 10 inches has a red piece x inches long removed and a blue piece x inches long added as shown in the figure below. Find the area of the white and blue rectangle.
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i tried (10+x)-(10-x) but i keep getting 2x and that doesn't seem right
i would love a picture, it is only fair since you get one ?
i have no idea i would assume you would have to do something along the lines of figuring out the area and perimeter in terms of x?
new width = 10-x new length = 10+x area = (10-x)(10+x)
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why x=10?
ignore me :P
ok
thanks
so 100-x^2 is the answer?
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(10-x)(10+x) = 100-x^2
yes!
ok
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