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condense the expression 1/2 log5 16-3log5 x+4log5 y
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hmmm ? I don't understand the equation.
\[1/2 \log_{5} 16- 3\log_{5} x+ 4\log_{5} y\]
do you know all the log rules?
if not - consult this page: http://www.purplemath.com/modules/logrules.htm you should then be able to solve this
yes i think i do
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an example step would be:\[3\log_5x=\log_5x^3\]
\[\frac 12 \log_5 16-3 \log_5 x+4 \log_5 y = \log_5 \frac{4 y^4}{x^3}\]
I guess FoolForMath has given away the answer - but try and do it yourself to convince yourself that this is the right answer :)
Yes I guess I am wrong.
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