Question

I need help with inequalities and finding the interval solution x^2-3x>=4

Answer 1

first, solve this EQUALITY: x^2 -3x -4 = 0

Answer 2

can you do that?

Answer 3

it can be written

\[x^2 - 3x - 4\ge 0\]

factorise

and then a simple method is to choose a point sy x = 1 and test the solution

in this case x = 1: -6>= 4 false so x = 1 isn't in the solution

so its x<= -1 and x >= 4

Answer 4

just a note (i'm not being picky here): the solution set to the inequality is the union of those two sets so it should be written as: x <= -1 OR x >= 4