Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).
Answer
y = 4/3x + 8
y = 4/3 x + 3
y = -3/4 x + 8
y = -3/4 x + 3

Answer 1

\[y=4/3x+8\]

Answer 2

// to the line => same slope
Slope of line 4x - 3y = -12
= -(4/-3) = 4/3

Equation required is
y-4 = (4/3) [x-(-3)]
y-4 = (4/3)x + 4
y = (4/3)x + 4+4
y = (4/3)x + 8