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OpenStudy (anonymous):
Half Angle Formula help? Square ((1+cos 4x) / 2)
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OpenStudy (anonymous):
cos 4x = 2cos^2(2x) - 1 so 1+ cos 4x = 1+2cos^2(2x) -1 = 2cos^2(2x)
OpenStudy (anonymous):
isnt is cos 2x?
OpenStudy (anonymous):
hmmm?
OpenStudy (anonymous):
cos 4x = cos 2(2x) right? so cos you can apply the formula of cos 2x for this
OpenStudy (anonymous):
oh you asked me for the final amswer??? yes it's cos 2x lol
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OpenStudy (anonymous):
haha yes. thank you!
OpenStudy (anonymous):
oh I want to correct the answer again it should be the absolute of cos2x which is more correct loo
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