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OpenStudy (anonymous):
(sin θ + cos θ) ^ 2 / (1+2sinθcosθ) = ??
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OpenStudy (anonymous):
Answer Choices: -sec^ 2 θ 1 0 1 - sin θ
OpenStudy (anonymous):
sin2 + cos2 = 1 so (sin + cos)^2 = sin2 + 2sin cos + cos2 =1 + 2sin cos then the answer is 1
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
I love identities
OpenStudy (anonymous):
I hate them -_-
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