Question

f(x)=x^2n / (2n)! . what is f'(x) ??

Answer 1

\[f'(x)=\frac{2nx^{2n-1}}{2n!}=\frac{nx^{2n-1}}{n!}\]

Answer 2

here is the \[\sum_{n=0}^{\infty} f(x)\]

Answer 3

weird the answer should be \[x ^{2n+1}/(2n+1)!\]