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lim x -> 1 x^2 - 1/x-1
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x->?
sorry x -> 1
\[\lim_{x \rightarrow 1}\frac{(x-1)(x+1)}{x-1}=\lim_{x \rightarrow 1}x+1=2\]
(x-1)(x+1)/(x-1) cancel the common bracket and put x =1 it will be (x+1)=(1+1)=2
Use the L'Hopital by finding derivatives till you get a solution.
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when do we factorize any limit ??
are there some rules for limits, if anyone can provide .. I will appreciate.
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