Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).
Answer
y =1/3 x - 3
y = 1/3 x + 17
y = -3x - 3
y = -3x + 17

Answer 1

y=mx+b , m=1/3 ; (6,-1)
-1=1/3(6)+b
-1=2+b
b=-3

=> y=1/3x-3