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Mathematics 20 Online
OpenStudy (anonymous):

(x-2)^2-16=0

OpenStudy (anonymous):

\[(x-2)^2-16=0 \]

OpenStudy (anonymous):

Solve for x?

OpenStudy (anonymous):

Solution #1 x^2-4x+4-16=0 x^2-4x-12=0 (x-6)(x+2)=0 x=-2,6 Solution #2 (x-2)^2=16 x-2=4 or x-2=-4 x=6 or x=-2

myininaya (myininaya):

\[(x-2)^2=16 \text{ added 16 on both sides} \] \[x-2=\pm \sqrt{16} \text{ took square root of both sides }\]

myininaya (myininaya):

I leave the rest to you

OpenStudy (anonymous):

i cannot undestend here x^2-4x-12=0 (x-6)(x+2)=0

myininaya (myininaya):

@Labinot you don't have to factor Your question requires no factoring

myininaya (myininaya):

Look at what I have done for you so far above

OpenStudy (anonymous):

ok than you

myininaya (myininaya):

We want to isolate x But we have minus 2 How do you do subtraction of 2? You need to ..................?

OpenStudy (anonymous):

\[(2x+1)^2-4=0\]

OpenStudy (anonymous):

is the x1=1/2 x2=-3/2

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