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(x-2)^2-16=0
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\[(x-2)^2-16=0 \]
Solve for x?
Solution #1 x^2-4x+4-16=0 x^2-4x-12=0 (x-6)(x+2)=0 x=-2,6 Solution #2 (x-2)^2=16 x-2=4 or x-2=-4 x=6 or x=-2
\[(x-2)^2=16 \text{ added 16 on both sides} \] \[x-2=\pm \sqrt{16} \text{ took square root of both sides }\]
I leave the rest to you
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i cannot undestend here x^2-4x-12=0 (x-6)(x+2)=0
@Labinot you don't have to factor Your question requires no factoring
Look at what I have done for you so far above
ok than you
We want to isolate x But we have minus 2 How do you do subtraction of 2? You need to ..................?
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\[(2x+1)^2-4=0\]
is the x1=1/2 x2=-3/2
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