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OpenStudy (anonymous):
FACTOR COMPETLEY 3Y^2-7Y+4 THANKS
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jimthompson5910 (jim_thompson5910):
3y^2-7y+4 3y^2-3y-4y+4 (3y^2-3y)+(-4y+4) 3y(y-1)+(-4y+4) 3y(y-1)-4(y-1) (3y-4)(y-1) So 3y^2-7y+4 factors to (3y-4)(y-1)
OpenStudy (anonymous):
OOO OKAY THANK YOU
jimthompson5910 (jim_thompson5910):
you're welcome
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