Question

Solve sinθcosθ-cosθ=0 for 0≤θ<2π

Answer 1

I have done the following:

cosθ(sinθ-1)=0

Using Zero-Product Property

either cosθ=0 which gives θ=π/2

or sinθ-1=0 ==> sinθ=1 which gives θ= π/2

Are there other possible values of the angle θ within the given range?????

Answer 2

\[ \cos(\theta) = 0 \rightarrow \frac{\pi}{2} \text{ or } \frac{3\pi}{2} \]