Question

A rocket is propelled vertically into the air from a height of 45 feet with an initial velocity of 572 ft/sec. If only the effect of gravity is considered, determine the average velocity from t=5 to t=8.2

Answer 1

Is it something like:
1/(8.2-5) Integral from 5 to 8.2 of 572
That would be the average velocity

Answer 2

\[(1/(8.2-5)) \int\limits_{5}^{8.2}572 dx\]