How would you draw a cylinder for the shell method for the region that is enclosed by x = pi/2, x = -pi/2 and y = cosx?

This is rotated about y = -1.

Question

How would you draw a cylinder for the shell method for the region that is enclosed by x = pi/2, x = -pi/2 and y = cosx? 

This is rotated about y = -1.

anonymous · Answer

@FoolForMath 
@myininaya 
@experimentX
@shivam_bhalla
@amistre64
@Zarkon
@Hero 

Anyone?

anonymous · Answer

@jim_thompson5910

anonymous · Answer

the definite integrand of f(x)=cosx from -pi/2 to pi/2
sinx from -pi/2 to pi/2 = 1-(-1)=2

anonymous · Answer

I do not want the answer. @akamushi

anonymous · Answer

@FoolForMath 
@myininaya 
@experimentX
@shivam_bhalla
@amistre64
@Zarkon
@Hero 

Anyone?

anonymous · Answer

@FoolForMath 
@myininaya 
@experimentX
@shivam_bhalla
@amistre64
@Zarkon
@Hero 

Anyone?

lgbasallote · Answer

@lgbasallote lol jk...idk shell using trig functions

anonymous · Answer

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